Generating Random Number In A Range With Java

One standard pattern for accomplishing this is:

Min + (int)(Math.random() * ((Max - Min) + 1))

The java Math library function Math.random() generates a double value in the range [0,1).
Notice this range does not include the 1.In order to get a specific range of values first you need to multiply by the magnitude of the range of values you want covered.
. 

Math.random() * ( Max - Min )

This returns a value in the range [0,Max-Min).

For example if you want [5,10] you need cover 5 integer values so you use

Math.random() * 5

This would return a value in the range [0,5)

Now you need to shift this range up to the range that you are targeting. You do this by adding the Min value.

Min + (Math.random() * (Max - Min))

You now will get a value in the range [Min,Max). Following our example, that means [5,10):

5 + (Math.random() * (10 - 5))

But, this is still doesn't include Max and you are getting a double value. In order to get the Max value included, you need to add 1 to your range parameter (Max - Min) and then truncate the decimal part by casting to an int. This is accomplished via:

Min + (int)(Math.random() * ((Max - Min) + 1))

And there you have it. A random integer value in the range [Min,Max], or per the example [5,10]:

5 + (int)(Math.random() * ((10 - 5) + 1))