Java is always pass-by-value. The difficult thing can be to understand that Java passes objects as references passed by value.
It goes like this:
It goes like this:
public void foo(Dog d) { d.name.equals("Max"); // true d = new Dog("Fifi"); d.name.equals("Fifi"); // true } Dog aDog = new Dog("Max"); foo(aDog); aDog.name.equals("Max"); // trueIn this example aDog.name will still be "Max". "d" is not overwritten in the function as the object reference is passed by value. Likewise:
public void foo(Dog d) { d.name.equals("Max"); // true d.setname("Fifi"); } Dog aDog = new Dog("Max"); foo(aDog); aDog.name.equals("Fifi"); // true
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