non-restoring binary divide, twos complement 4-bit numbers note: 7 = 0 1 1 1 -7 = 1 0 0 1 1 1 0 0 quotient ________________ 0 1 1 1 / 0 1 0 1 0 1 0 1 pre shift +1 0 0 1 adding twos complement of divisor _______ 10 - 7 = 3 0 0 1 1 1 quotient=1 +1 0 0 1 next bit subtract _______ 7 - 7 = 0 0 0 0 0 0 quotient=1 +1 0 0 1 next bit subtract _______ 0 - 7 = -7 1 0 0 1 1 quotient=0 +0 1 1 1 adding divisor next bit add _______ 2 + 7 = 9 = -7 1 0 1 0 quotient=0 +0 1 1 1 correction add _______ final remainder 0 0 0 1 remainder (5 cycles using adder)
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Program for Implementation of Non-Restoring Algorithm.
Saturday, 1 June 2013
Program for Implementation of Non-Restoring Algorithm.
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